Flat Earth 101
If all you learn here is 8 inches per mile squared, you pass.
Please download this graphic. This math is easy to confirm.
Since this curvature cannot be found on earth, we are left to assume the earth is flat. Default is flat because that’s what you see and anything else is a belief system that doesn’t apply to reality when it must. The curvature over water has to be 8 inches per square mile, no more or less. If you end up measuring less over water, the size of the entire earth has to change at the equator and since it’s a ball — it has to change longitudinally as well making earth impossibly large based upon the actual measurements that you do on this plane of existence.
I’m measuring light 10 to 20,000 miles away with HOW TO TELL TIME BY THE MOON but if you can come up with 10 miles to measure across water, you can figure this out since the curvature should be 66.66 feet — which is a substantial height/depth; most towns don’t even have a structure that tall. If your zoom isn’t great it will be sunk into the horizon but the zoom can bring it right into focus.
You can see me argue these points here
2nd Geekroom Debate
Red’s Rhetoric is just that… rhetoric to no end and no evidence. This poor Sith Lord should be in your prayers. He loses every debate but he says he’s a rocket scientist.
When's the ball earth coming out?
These goofballs have had 500 years to show you a model that falls apart the first time you pay attention to ANY detail.
We have jets that go the speed of sound 767 mph. Using the curvature formula, 8” per mile squared—a jet at Mach 1 would have to drop 74 miles the first hour — incrementally. A jet traveling Mach 2 would need to drop 297 miles incrementally after one hour. In March 2004, the X-43A set the previous record of Mach 6.8 (nearly 5,000 mph). That means that after one hour, it would need to drop 4,000 miles incrementally, (the radius of earth). Since then NASA has been working towards Mach 10 with this craft, that’s 7,670 mph which necessitates 7,427 miles of drop after one hour. That’s a drop of 124 miles per minute (avg isn’t an accurate depiction because there is a quicker decline the further from your home airports level that you set your gyroscope with.) or over 2 miles a second. Drop is the appropriate word because it cannot be achieved by angling alone. Instrumentation — altimeters and gyroscopes – register none of this. Considering we aren’t terribly sure what’s up above 120,000 feet or 25 miles, the numbers don’t add up even if we consider twice that distance claimed for NASA’s X series.
The tiny solar eclipse shadow CANNOT be negotiated any other way; It proves a small moon.
Any lunar eclipse where the shadow comes from the side disprove the helios model
The sun doesn’t behave like an explosion.
…on a side note.
Magellanic bridge
Still no answer
All the evidence you need to admit there's a problem now?
What you should be able to prove if the ball were real.
Gravity
Curve
Instrumentation
Spin
You don’t need me to figure this out. If someone could prove this ball exists, they would have.
If you need more
There’s been so much work on this with 100% precision that’s been reviewed by millions already that there is very little point in repeating it. The only evidence in existence is flat earth evidence and proof. This is more spiritual than scientific because scientifically, THERE IS NO REASON TO BELIEVE IN THE SPINNING BALL EARTH FLYING THROUGH A VACUUM.